chewbaca
Experienced Member
- Reaction score
- 1
Its known that male pattern baldness is inherited from Mum's X gene only for male offspring.....Mum determines baldness trait for boys(XY) while both mum and dad dtermines the baldness trait for girls(XX)....FOR MALES ONLY X GENE which is basically MUM, WHEREAS FOR FEMALES BOTH MUM AND DAD IS THE FACTOR FOR male pattern baldness..let's calculate
General science is Female = XX and Male = XY (Note that for females which is XX, The 2ndX is from the father wheareas for male which is XY, there is no X gene to inherit from his own Dad,only Y which is not a factor for male pattern baldness).So here's how u were born as male or female..its the sperm of the dad which decides to give X or Y to mum, thus determing the sex of a baby.Note mum only contributes X but Dad can contribute both X or Y..but one parent can only contribute one gene to make a baby
X(mum)+X(dad sperm)= XX (baby girl)
X(mum) + Y (dad sperm) = XY (baby boy)
Now to find out if your mum has inherited from her own mum/dad the baldness trait( reember for females both parties play a part).THis is how u break down.starting from yr mum (females are XX format) , u have to find out if she has the Xb gene inherited from her own parents.eITHER FROM FAHER OR MOTHER OR BOTH
Xn=Normal gene from her EITHER parents
Xb=Baldness gene from her EITHER parents
Both combine to produce X_X_ WHICH IS YOUR MUM , A FEMALE
Both X chromosomes with normal gene represented by Xn Xn this would appear as normal female with no baldness trait. One normal and one baldness gene on the X chromosome pair represented by Xn Xb, this would appear as normal female too with a dormant baldness trait OFFSETTED. Both X chromosomes with the baldness gene represented by Xb Xb, this would appear as a woman with pattern baldness
So yr mum if she is not losing hair she is either XnXn or XnXb (normal),
if she is losing hair she is XbXb (mum with pattern baldness)
And then her husband (your own dad) comes in with his Y from his sperm and u are born
XnXn(normal mum)+Y =XnY (son without male pattern baldness inheritance)
XbXn(normal mum)+Y = XbY (son with male pattern baldness inheritance)
XbXb(bald mum)+Y = XbY (son with male pattern baldness inheritance)
The above 3 equations show that a male has to inherit the Xb gene specifically from his mother's coding to suffer from male pattern baldness, not from his father as he only contributes Y for male baby, not a factor gene for male pattern baldness as mentioned earlier for males.....So it doesnt mattter if yr mum suffers from hair loss or not...THe trait could still be there lying dormant (eg.XbXn) for : Reason is that there is another Xn there to offset the trait which is why she doesnt suffer.and in turn u as a male child has inherited her Xb gene as the dominant and u have no Xn from yr own DAD to offset it....which is why u have male pattern baldness!!...to get that Xn from your own dad, u have to born a female making it XbXn - offsetted case..THE BALDNESS TRAIT IS ONLY FOUND IN X CLASS GENE AND X CLASS IS ALSO CONTRIBUTED BY DAD FOR MAKING A GIRL(XX) SUPPORTING THE ABOVE HYPOTHESES AND ON WHY FEMALES ALSO SUFFER FROM HAIR LOSS..THEY HAVE BOTH X_X_..THIS PROVES THAT Y FROM FATHER DOESNT PLAY A PART IN male pattern baldness AS ITS NON EXISTENT IN FEMALE BABIES
Update at the bottom of the page
So this suggest that if u are male u gotta look at both yr Grandpa,grandmum and MUM to see if they are bald and passed it on to your own MUM whch in turn pass it to u...not your own father and his own parents as he only play a factor for baby girl with male pattern baldness, tat is if u have a sis, she looks at both your mum and dad and their respective grandparents while u must look at your MATERNAL BLOODLINE ONLY.....As for yr sis...your parents play a part for Baldness trait as they gave both X..if she is XbXb, she has the trait as both baldness genes are inherited from both mum and dad Update: for those havng difficulty nderstanding here is a pictorial diagram ,scroll down on the page link :
General science is Female = XX and Male = XY (Note that for females which is XX, The 2ndX is from the father wheareas for male which is XY, there is no X gene to inherit from his own Dad,only Y which is not a factor for male pattern baldness).So here's how u were born as male or female..its the sperm of the dad which decides to give X or Y to mum, thus determing the sex of a baby.Note mum only contributes X but Dad can contribute both X or Y..but one parent can only contribute one gene to make a baby
X(mum)+X(dad sperm)= XX (baby girl)
X(mum) + Y (dad sperm) = XY (baby boy)
Now to find out if your mum has inherited from her own mum/dad the baldness trait( reember for females both parties play a part).THis is how u break down.starting from yr mum (females are XX format) , u have to find out if she has the Xb gene inherited from her own parents.eITHER FROM FAHER OR MOTHER OR BOTH
Xn=Normal gene from her EITHER parents
Xb=Baldness gene from her EITHER parents
Both combine to produce X_X_ WHICH IS YOUR MUM , A FEMALE
Both X chromosomes with normal gene represented by Xn Xn this would appear as normal female with no baldness trait. One normal and one baldness gene on the X chromosome pair represented by Xn Xb, this would appear as normal female too with a dormant baldness trait OFFSETTED. Both X chromosomes with the baldness gene represented by Xb Xb, this would appear as a woman with pattern baldness
So yr mum if she is not losing hair she is either XnXn or XnXb (normal),
if she is losing hair she is XbXb (mum with pattern baldness)
And then her husband (your own dad) comes in with his Y from his sperm and u are born
XnXn(normal mum)+Y =XnY (son without male pattern baldness inheritance)
XbXn(normal mum)+Y = XbY (son with male pattern baldness inheritance)
XbXb(bald mum)+Y = XbY (son with male pattern baldness inheritance)
The above 3 equations show that a male has to inherit the Xb gene specifically from his mother's coding to suffer from male pattern baldness, not from his father as he only contributes Y for male baby, not a factor gene for male pattern baldness as mentioned earlier for males.....So it doesnt mattter if yr mum suffers from hair loss or not...THe trait could still be there lying dormant (eg.XbXn) for : Reason is that there is another Xn there to offset the trait which is why she doesnt suffer.and in turn u as a male child has inherited her Xb gene as the dominant and u have no Xn from yr own DAD to offset it....which is why u have male pattern baldness!!...to get that Xn from your own dad, u have to born a female making it XbXn - offsetted case..THE BALDNESS TRAIT IS ONLY FOUND IN X CLASS GENE AND X CLASS IS ALSO CONTRIBUTED BY DAD FOR MAKING A GIRL(XX) SUPPORTING THE ABOVE HYPOTHESES AND ON WHY FEMALES ALSO SUFFER FROM HAIR LOSS..THEY HAVE BOTH X_X_..THIS PROVES THAT Y FROM FATHER DOESNT PLAY A PART IN male pattern baldness AS ITS NON EXISTENT IN FEMALE BABIES
Update at the bottom of the page
So this suggest that if u are male u gotta look at both yr Grandpa,grandmum and MUM to see if they are bald and passed it on to your own MUM whch in turn pass it to u...not your own father and his own parents as he only play a factor for baby girl with male pattern baldness, tat is if u have a sis, she looks at both your mum and dad and their respective grandparents while u must look at your MATERNAL BLOODLINE ONLY.....As for yr sis...your parents play a part for Baldness trait as they gave both X..if she is XbXb, she has the trait as both baldness genes are inherited from both mum and dad Update: for those havng difficulty nderstanding here is a pictorial diagram ,scroll down on the page link :
:hairy: